Ruby
## Day 16 of 30 - Ruby Coding Challenge - Sum Even Numbers in a Fibonacci Sequence

## Fibonacci Sequence in Ruby

## Sum Even Numbers in a Fibonacci Sequence in Ruby

Hey friends!

This is the blog post version of the Youtube video from the 30 Ruby Coding Challenges in 30 Days series

We’ve solved the Fibonacci sequence here, here and here, which means that we have some clues of how to create a Fibonacci sequence :)

Today we want to be a little bit daring by solving the following problem:

I want to sum all even numbers in a Fibonacci sequence

As you already know, this is one of the solutions:

```
def fibonacci_sum(count)
number = 0
sequence = []
(0..count).each do |item|
number = item if item <= 1
number = sequence[-1] + sequence[-2] if item > 1
sequence << number
end
sequence
end
```

We’re returning a Fibonacci sequence, however, that’s not what we’re looking for

We’re going to:

- add a local variable called
**sum** - then update this variable
**only if the number is even** - return the
**sum**variable

```
def fibonacci_sum(count)
sum = 0
number = 0
sequence = []
(0..count).each do |item|
number = item if item <= 1
number = sequence[-1] + sequence[-2] if item > 1
sequence << number
sum += number if number % 2 == 0
end
sum
end
```

Math comes handy here. An even number is a number dividable by 2, which in Ruby is represented by

```
number % 2 == 0
```

Quite simple, isn’t it? ðŸ˜¬

In the next video, we’re going to explore a decent and beautiful Ruby Way to solve this same problem, see you there :)

Thanks for the visit and see you in the next coding challenge!

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